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T-test
Options consider:
Confidence intervals
Mean 1: 1.813
Mean 2: 2.03
N1: 4
N2: 4
Std Dev.1: 0.01245
Std Dev.2: 0.01103

t (0.025) for 95% CI= 2.3806
declare p larger than alpha=0.05 not significant.

mean1 eq: 1.813 (var1= 0) (se= 0.006)
mean2 eq: 2.03 (var2= 0) (se= 0.006)

Probability that var1<var2
p=0.42347 (left: 0.5765; double: 0.847)

Difference between means:
M1-M2=1.813-2.03=-0.217
sd=0.0198; se=0.0083
95% CI of difference:
-0.2368 <-0.217< -0.1972 (Wald)
t-difference: -26.092
df-t: 5.2; p= 0
(left p: 1; two sided: 0)

For help go to SISA
More:

Calculate the minimum Sample
Size required to see if the
difference between 1.81 and 2.03
is statistically significant

Calculate CI
around Mean1= 1.813.

Calculate CI
around Mean2= 2.03.